tag:blogger.com,1999:blog-7408771368678736593.post6037386027907460793..comments2021-04-25T00:12:27.183-07:00Comments on QUANTOMANIA: Perfect squarePROBLEM SMOKERhttp://www.blogger.com/profile/03560832495155646004noreply@blogger.comBlogger1125tag:blogger.com,1999:blog-7408771368678736593.post-46674913927025114222011-08-31T11:18:10.991-07:002011-08-31T11:18:10.991-07:001st question is equivalent to (n+12)^...1st question is equivalent to (n+12)^2-123 is a pf. square, (n+12)^2=k^2+123,<br />so if 123=2p-1, then p=62,<br />so if n+12 =62, then k=61, so for n=50 and n=-74, the expression is a pf. square<br />mayankAnonymousnoreply@blogger.com